Base | Representation |
---|---|
bin | 10011100000010010100… |
… | …100000000001110011001 |
3 | 11202010122200110222112100 |
4 | 103200102210000032121 |
5 | 133430004323134340 |
6 | 2503424432034013 |
7 | 165556622266344 |
oct | 23402244001631 |
9 | 4663580428470 |
10 | 1340341224345 |
11 | 477487751122 |
12 | 197925692909 |
13 | 99516a7c6a6 |
14 | 48c311bb45b |
15 | 24cea860830 |
hex | 13812900399 |
1340341224345 has 48 divisors (see below), whose sum is σ = 2325515092992. Its totient is φ = 714154648320.
The previous prime is 1340341224331. The next prime is 1340341224403. The reversal of 1340341224345 is 5434221430431.
1340341224345 is a `hidden beast` number, since 1 + 3 + 403 + 4 + 1 + 2 + 243 + 4 + 5 = 666.
It is not a de Polignac number, because 1340341224345 - 26 = 1340341224281 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 395262600 + ... + 395265990.
It is an arithmetic number, because the mean of its divisors is an integer number (48448231104).
Almost surely, 21340341224345 is an apocalyptic number.
1340341224345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1340341224345 is a deficient number, since it is larger than the sum of its proper divisors (985173868647).
1340341224345 is a wasteful number, since it uses less digits than its factorization.
1340341224345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9342 (or 9339 counting only the distinct ones).
The product of its (nonzero) digits is 138240, while the sum is 36.
Adding to 1340341224345 its reverse (5434221430431), we get a palindrome (6774562654776).
The spelling of 1340341224345 in words is "one trillion, three hundred forty billion, three hundred forty-one million, two hundred twenty-four thousand, three hundred forty-five".
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