1340341730537 has 4 divisors (see below), whose sum is σ = 1340355623040. Its totient is φ = 1340327838036.

The previous prime is 1340341730477. The next prime is 1340341730543. The reversal of 1340341730537 is 7350371430431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340341730537 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340341730494 and 1340341730503.

It is not an unprimeable number, because it can be changed into a prime (1340341730437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6800513 + ... + 6994830.

It is an arithmetic number, because the mean of its divisors is an integer number (335088905760).

Almost surely, 2^{1340341730537} is an apocalyptic number.

It is an amenable number.

1340341730537 is a deficient number, since it is larger than the sum of its proper divisors (13892503).

1340341730537 is an equidigital number, since it uses as much as digits as its factorization.

1340341730537 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13892502.

The product of its (nonzero) digits is 317520, while the sum is 41.

The spelling of 1340341730537 in words is "one trillion, three hundred forty billion, three hundred forty-one million, seven hundred thirty thousand, five hundred thirty-seven".