Base | Representation |
---|---|
bin | 11000111101110100… |
… | …00000010111010011 |
3 | 1021121002220111102221 |
4 | 30132322000113103 |
5 | 204422234033321 |
6 | 10054001521511 |
7 | 653102140342 |
oct | 143672002723 |
9 | 37532814387 |
10 | 13403424211 |
11 | 5758979aa1 |
12 | 2720943297 |
13 | 1357b41a58 |
14 | 912181b59 |
15 | 536a8ee41 |
hex | 31ee805d3 |
13403424211 has 4 divisors (see below), whose sum is σ = 13407158232. Its totient is φ = 13399690192.
The previous prime is 13403424193. The next prime is 13403424259. The reversal of 13403424211 is 11242430431.
13403424211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13403424211 - 29 = 13403423699 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13403424511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1861621 + ... + 1868806.
It is an arithmetic number, because the mean of its divisors is an integer number (3351789558).
Almost surely, 213403424211 is an apocalyptic number.
13403424211 is a deficient number, since it is larger than the sum of its proper divisors (3734021).
13403424211 is an equidigital number, since it uses as much as digits as its factorization.
13403424211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3734020.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13403424211 its reverse (11242430431), we get a palindrome (24645854642).
The spelling of 13403424211 in words is "thirteen billion, four hundred three million, four hundred twenty-four thousand, two hundred eleven".
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