1340344204433 has 16 divisors (see below), whose sum is σ = 1459769512656. Its totient is φ = 1223275806720.

The previous prime is 1340344204429. The next prime is 1340344204483. The reversal of 1340344204433 is 3344024430431.

It can be written as a sum of positive squares in 8 ways, for example, as 375446631169 + 964897573264 = 612737^2 + 982292^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340344204433 - 2² = 1340344204429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340344204393 and 1340344204402.

It is not an unprimeable number, because it can be changed into a prime (1340344204403) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 752753 + ... + 1802033.

It is an arithmetic number, because the mean of its divisors is an integer number (91235594541).

Almost surely, 2^{1340344204433} is an apocalyptic number.

1340344204433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1340344204433 is a deficient number, since it is larger than the sum of its proper divisors (119425308223).

1340344204433 is a wasteful number, since it uses less digits than its factorization.

1340344204433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1050404.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 1340344204433 its reverse (3344024430431), we get a palindrome (4684368634864).

The spelling of 1340344204433 in words is "one trillion, three hundred forty billion, three hundred forty-four million, two hundred four thousand, four hundred thirty-three".