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134040103 = 832416701
BaseRepresentation
bin1111111110101…
…00101000100111
3100100012221110021
413333110220213
5233303240403
621144540011
73215215321
oct777245047
9310187407
10134040103
116973134a
1238a81607
1321a01692
1413b32611
15bb7a8bd
hex7fd4a27

134040103 has 8 divisors (see below), whose sum is σ = 136238256. Its totient is φ = 131856000.

The previous prime is 134040097. The next prime is 134040107. The reversal of 134040103 is 301040431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134040103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134040107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16653 + ... + 23353.

It is an arithmetic number, because the mean of its divisors is an integer number (17029782).

Almost surely, 2134040103 is an apocalyptic number.

134040103 is a deficient number, since it is larger than the sum of its proper divisors (2198153).

134040103 is an equidigital number, since it uses as much as digits as its factorization.

134040103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7025.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 134040103 is about 11577.5689589827. The cubic root of 134040103 is about 511.7740384235.

Adding to 134040103 its reverse (301040431), we get a palindrome (435080534).

The spelling of 134040103 in words is "one hundred thirty-four million, forty thousand, one hundred three".

Divisors: 1 83 241 6701 20003 556183 1614941 134040103