1340404040141 has 4 divisors (see below), whose sum is σ = 1342751508384. Its totient is φ = 1338056571900.

The previous prime is 1340404040137. The next prime is 1340404040149. The reversal of 1340404040141 is 1410404040431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340404040141 - 2² = 1340404040137 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1340404040141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340404040149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1173733265 + ... + 1173734406.

It is an arithmetic number, because the mean of its divisors is an integer number (335687877096).

Almost surely, 2^{1340404040141} is an apocalyptic number.

It is an amenable number.

1340404040141 is a deficient number, since it is larger than the sum of its proper divisors (2347468243).

1340404040141 is an equidigital number, since it uses as much as digits as its factorization.

1340404040141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2347468242.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 1340404040141 its reverse (1410404040431), we get a palindrome (2750808080572).

The spelling of 1340404040141 in words is "one trillion, three hundred forty billion, four hundred four million, forty thousand, one hundred forty-one".