Base | Representation |
---|---|
bin | 11000111101111000… |
… | …11011111010001001 |
3 | 1021121011002212101121 |
4 | 30132330123322021 |
5 | 204422414430241 |
6 | 10054023315241 |
7 | 653110432660 |
oct | 143674337211 |
9 | 37534085347 |
10 | 13404061321 |
11 | 5759274732 |
12 | 2720babb21 |
13 | 1358005a41 |
14 | 9122a9dd7 |
15 | 536b68ad1 |
hex | 31ef1be89 |
13404061321 has 4 divisors (see below), whose sum is σ = 15318927232. Its totient is φ = 11489195412.
The previous prime is 13404061291. The next prime is 13404061337. The reversal of 13404061321 is 12316040431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13404061321 - 217 = 13403930249 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13404061361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 957432945 + ... + 957432958.
It is an arithmetic number, because the mean of its divisors is an integer number (3829731808).
Almost surely, 213404061321 is an apocalyptic number.
It is an amenable number.
13404061321 is a deficient number, since it is larger than the sum of its proper divisors (1914865911).
13404061321 is an equidigital number, since it uses as much as digits as its factorization.
13404061321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1914865910.
The product of its (nonzero) digits is 1728, while the sum is 25.
The spelling of 13404061321 in words is "thirteen billion, four hundred four million, sixty-one thousand, three hundred twenty-one".
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