13404074268451 has 4 divisors (see below), whose sum is σ = 13404377551672. Its totient is φ = 13403770985232.

The previous prime is 13404074268437. The next prime is 13404074268491. The reversal of 13404074268451 is 15486247040431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13404074268451 - 2⁵ = 13404074268419 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13404074268395 and 13404074268404.

It is not an unprimeable number, because it can be changed into a prime (13404074268491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151575306 + ... + 151663711.

It is an arithmetic number, because the mean of its divisors is an integer number (3351094387918).

Almost surely, 2^{13404074268451} is an apocalyptic number.

13404074268451 is a deficient number, since it is larger than the sum of its proper divisors (303283221).

13404074268451 is an equidigital number, since it uses as much as digits as its factorization.

13404074268451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 303283220.

The product of its (nonzero) digits is 2580480, while the sum is 49.

The spelling of 13404074268451 in words is "thirteen trillion, four hundred four billion, seventy-four million, two hundred sixty-eight thousand, four hundred fifty-one".