Base | Representation |
---|---|
bin | 1100001100001110000100… |
… | …0101011101011100010101 |
3 | 1202110102020222112011212022 |
4 | 3003003201011131130111 |
5 | 3224103021003042222 |
6 | 44301425142302525 |
7 | 2552261312251136 |
oct | 303034105353425 |
9 | 52412228464768 |
10 | 13404074268437 |
11 | 42a86aa532296 |
12 | 1605971427a45 |
13 | 762cca41c788 |
14 | 344a91351c8d |
15 | 183a0dac6042 |
hex | c30e115d715 |
13404074268437 has 2 divisors, whose sum is σ = 13404074268438. Its totient is φ = 13404074268436.
The previous prime is 13404074268419. The next prime is 13404074268491. The reversal of 13404074268437 is 73486247040431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10385240992996 + 3018833275441 = 3222614^2 + 1737479^2 .
It is a cyclic number.
It is not a de Polignac number, because 13404074268437 - 26 = 13404074268373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13404074268737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702037134218 + 6702037134219.
It is an arithmetic number, because the mean of its divisors is an integer number (6702037134219).
Almost surely, 213404074268437 is an apocalyptic number.
It is an amenable number.
13404074268437 is a deficient number, since it is larger than the sum of its proper divisors (1).
13404074268437 is an equidigital number, since it uses as much as digits as its factorization.
13404074268437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10838016, while the sum is 53.
The spelling of 13404074268437 in words is "thirteen trillion, four hundred four billion, seventy-four million, two hundred sixty-eight thousand, four hundred thirty-seven".
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