Base | Representation |
---|---|
bin | 11000111101111001… |
… | …00000111100001011 |
3 | 1021121011010220122221 |
4 | 30132330200330023 |
5 | 204422421110211 |
6 | 10054023554511 |
7 | 653110550032 |
oct | 143674407413 |
9 | 37534126587 |
10 | 13404081931 |
11 | 5759289169 |
12 | 2720bbba37 |
13 | 1358012236 |
14 | 9122b3719 |
15 | 536b6ec71 |
hex | 31ef20f0b |
13404081931 has 4 divisors (see below), whose sum is σ = 13436073000. Its totient is φ = 13372090864.
The previous prime is 13404081883. The next prime is 13404081973. The reversal of 13404081931 is 13918040431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13918040431 = 181 ⋅76895251.
It is a cyclic number.
It is not a de Polignac number, because 13404081931 - 233 = 4814147339 is a prime.
It is a super-2 number, since 2×134040819312 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13404081331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15994906 + ... + 15995743.
It is an arithmetic number, because the mean of its divisors is an integer number (3359018250).
Almost surely, 213404081931 is an apocalyptic number.
13404081931 is a deficient number, since it is larger than the sum of its proper divisors (31991069).
13404081931 is an equidigital number, since it uses as much as digits as its factorization.
13404081931 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31991068.
The product of its (nonzero) digits is 10368, while the sum is 34.
The spelling of 13404081931 in words is "thirteen billion, four hundred four million, eighty-one thousand, nine hundred thirty-one".
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