13404222241 has 4 divisors (see below), whose sum is σ = 13404829572. Its totient is φ = 13403614912.

The previous prime is 13404222229. The next prime is 13404222263. The reversal of 13404222241 is 14222240431.

13404222241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14222240431 = 7 ⋅2031748633.

It can be written as a sum of positive squares in 2 ways, for example, as 978438400 + 12425783841 = 31280^2 + 111471^2 .

It is a cyclic number.

It is not a de Polignac number, because 13404222241 - 2³³ = 4814287649 is a prime.

It is a super-2 number, since 2×13404222241² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13404222281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 269260 + ... + 315133.

It is an arithmetic number, because the mean of its divisors is an integer number (3351207393).

Almost surely, 2^13404222241 is an apocalyptic number.

It is an amenable number.

13404222241 is a deficient number, since it is larger than the sum of its proper divisors (607331).

13404222241 is an equidigital number, since it uses as much as digits as its factorization.

13404222241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 607330.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 13404222241 its reverse (14222240431), we get a palindrome (27626462672).

The spelling of 13404222241 in words is "thirteen billion, four hundred four million, two hundred twenty-two thousand, two hundred forty-one".