13404265403 has 4 divisors (see below), whose sum is σ = 13409584968. Its totient is φ = 13398945840.

The previous prime is 13404265387. The next prime is 13404265409. The reversal of 13404265403 is 30456240431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30456240431 = 2671 ⋅11402561.

It is a cyclic number.

It is not a de Polignac number, because 13404265403 - 2⁴ = 13404265387 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13404265403.

It is not an unprimeable number, because it can be changed into a prime (13404265409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2656001 + ... + 2661042.

It is an arithmetic number, because the mean of its divisors is an integer number (3352396242).

Almost surely, 2^13404265403 is an apocalyptic number.

13404265403 is a deficient number, since it is larger than the sum of its proper divisors (5319565).

13404265403 is an equidigital number, since it uses as much as digits as its factorization.

13404265403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5319564.

The product of its (nonzero) digits is 34560, while the sum is 32.

The spelling of 13404265403 in words is "thirteen billion, four hundred four million, two hundred sixty-five thousand, four hundred three".