13404310531 has 8 divisors (see below), whose sum is σ = 13772433024. Its totient is φ = 13036495680.

The previous prime is 13404310499. The next prime is 13404310537. The reversal of 13404310531 is 13501340431.

13404310531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13404310531 - 2⁵ = 13404310499 is a prime.

It is a super-2 number, since 2×13404310531² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13404310496 and 13404310505.

It is not an unprimeable number, because it can be changed into a prime (13404310537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12846 + ... + 164236.

It is an arithmetic number, because the mean of its divisors is an integer number (1721554128).

Almost surely, 2^13404310531 is an apocalyptic number.

13404310531 is a deficient number, since it is larger than the sum of its proper divisors (368122493).

13404310531 is a wasteful number, since it uses less digits than its factorization.

13404310531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153821.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 13404310531 its reverse (13501340431), we get a palindrome (26905650962).

The spelling of 13404310531 in words is "thirteen billion, four hundred four million, three hundred ten thousand, five hundred thirty-one".