13404402013 has 4 divisors (see below), whose sum is σ = 13438861020. Its totient is φ = 13369943008.

The previous prime is 13404402007. The next prime is 13404402019. The reversal of 13404402013 is 31020440431.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13404402007) and next prime (13404402019).

It can be written as a sum of positive squares in 2 ways, for example, as 9724523769 + 3679878244 = 98613^2 + 60662^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13404402013 is a prime.

It is a super-2 number, since 2×13404402013² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13404402019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17228920 + ... + 17229697.

It is an arithmetic number, because the mean of its divisors is an integer number (3359715255).

Almost surely, 2^13404402013 is an apocalyptic number.

It is an amenable number.

13404402013 is a deficient number, since it is larger than the sum of its proper divisors (34459007).

13404402013 is an equidigital number, since it uses as much as digits as its factorization.

13404402013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34459006.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13404402013 its reverse (31020440431), we get a palindrome (44424842444).

The spelling of 13404402013 in words is "thirteen billion, four hundred four million, four hundred two thousand, thirteen".