1340442301 has 4 divisors (see below), whose sum is σ = 1462300704. Its totient is φ = 1218583900.

The previous prime is 1340442289. The next prime is 1340442317. The reversal of 1340442301 is 1032440431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340442301 - 2⁵ = 1340442269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340442331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60929185 + ... + 60929206.

It is an arithmetic number, because the mean of its divisors is an integer number (365575176).

Almost surely, 2^1340442301 is an apocalyptic number.

1340442301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1340442301 is a deficient number, since it is larger than the sum of its proper divisors (121858403).

1340442301 is a wasteful number, since it uses less digits than its factorization.

1340442301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121858402.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 1340442301 is about 36612.0513082783. The cubic root of 1340442301 is about 1102.5950579200.

Adding to 1340442301 its reverse (1032440431), we get a palindrome (2372882732).

The spelling of 1340442301 in words is "one billion, three hundred forty million, four hundred forty-two thousand, three hundred one".