Base | Representation |
---|---|
bin | 11110011110100110101011… |
… | …000100100111011101111011 |
3 | 122120121112021222200112212102 |
4 | 132132212223010213131323 |
5 | 120032141121120030120 |
6 | 1153031110100534015 |
7 | 40143252531302426 |
oct | 3636465304473573 |
9 | 576545258615772 |
10 | 134044504455035 |
11 | 3978aa56260649 |
12 | 1304a8813b130b |
13 | 59a445b709685 |
14 | 2515b080149bd |
15 | 1076c12708d75 |
hex | 79e9ab12777b |
134044504455035 has 8 divisors (see below), whose sum is σ = 160857191188656. Its totient is φ = 107233079668960.
The previous prime is 134044504454897. The next prime is 134044504455119. The reversal of 134044504455035 is 530554405440431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 134044504455035 - 212 = 134044504450939 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 315253184 + ... + 315678093.
It is an arithmetic number, because the mean of its divisors is an integer number (20107148898582).
Almost surely, 2134044504455035 is an apocalyptic number.
134044504455035 is a deficient number, since it is larger than the sum of its proper divisors (26812686733621).
134044504455035 is an equidigital number, since it uses as much as digits as its factorization.
134044504455035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 630973773.
The product of its (nonzero) digits is 5760000, while the sum is 47.
Adding to 134044504455035 its reverse (530554405440431), we get a palindrome (664598909895466).
The spelling of 134044504455035 in words is "one hundred thirty-four trillion, forty-four billion, five hundred four million, four hundred fifty-five thousand, thirty-five".
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