13405145423234 has 4 divisors (see below), whose sum is σ = 20107718134854. Its totient is φ = 6702572711616.

The previous prime is 13405145423203. The next prime is 13405145423239. The reversal of 13405145423234 is 43232454150431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10457753484025 + 2947391939209 = 3233845^2 + 1716797^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13405145423191 and 13405145423200.

It is not an unprimeable number, because it can be changed into a prime (13405145423239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3351286355807 + ... + 3351286355810.

Almost surely, 2^{13405145423234} is an apocalyptic number.

13405145423234 is a deficient number, since it is larger than the sum of its proper divisors (6702572711620).

13405145423234 is an equidigital number, since it uses as much as digits as its factorization.

13405145423234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6702572711619.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 13405145423234 its reverse (43232454150431), we get a palindrome (56637599573665).

The spelling of 13405145423234 in words is "thirteen trillion, four hundred five billion, one hundred forty-five million, four hundred twenty-three thousand, two hundred thirty-four".