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13405215241 = 111771685643
BaseRepresentation
bin11000111110000001…
…10101101000001001
31021121020021111021101
430133000311220021
5204423213341431
610054104141401
7653123310115
oct143700655011
937536244241
1013405215241
115759992690
122721467861
13135831b032
149124ca745
15536ce5961
hex31f035a09

13405215241 has 8 divisors (see below), whose sum is σ = 15484099104. Its totient is φ = 11469702720.

The previous prime is 13405215233. The next prime is 13405215253. The reversal of 13405215241 is 14251250431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13405215241 - 23 = 13405215233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13405215221) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35842635 + ... + 35843008.

It is an arithmetic number, because the mean of its divisors is an integer number (1935512388).

Almost surely, 213405215241 is an apocalyptic number.

13405215241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13405215241 is a deficient number, since it is larger than the sum of its proper divisors (2078883863).

13405215241 is a wasteful number, since it uses less digits than its factorization.

13405215241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71685671.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 13405215241 its reverse (14251250431), we get a palindrome (27656465672).

The spelling of 13405215241 in words is "thirteen billion, four hundred five million, two hundred fifteen thousand, two hundred forty-one".

Divisors: 1 11 17 187 71685643 788542073 1218655931 13405215241