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13405215221 is a prime number
BaseRepresentation
bin11000111110000001…
…10101100111110101
31021121020021111020122
430133000311213311
5204423213341341
610054104141325
7653123310056
oct143700654765
937536244218
1013405215221
115759992672
122721467845
13135831b018
149124ca72d
15536ce594b
hex31f0359f5

13405215221 has 2 divisors, whose sum is σ = 13405215222. Its totient is φ = 13405215220.

The previous prime is 13405215191. The next prime is 13405215233. The reversal of 13405215221 is 12251250431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12053844100 + 1351371121 = 109790^2 + 36761^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13405215221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13405245221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702607610 + 6702607611.

It is an arithmetic number, because the mean of its divisors is an integer number (6702607611).

Almost surely, 213405215221 is an apocalyptic number.

It is an amenable number.

13405215221 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405215221 is an equidigital number, since it uses as much as digits as its factorization.

13405215221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 13405215221 its reverse (12251250431), we get a palindrome (25656465652).

The spelling of 13405215221 in words is "thirteen billion, four hundred five million, two hundred fifteen thousand, two hundred twenty-one".