Base | Representation |
---|---|
bin | 10011100000011101111… |
… | …000011110110101111101 |
3 | 11202011010220211210121001 |
4 | 103200131320132311331 |
5 | 133430401433021023 |
6 | 2503455334410301 |
7 | 165564416462230 |
oct | 23403570366575 |
9 | 4664126753531 |
10 | 1340531142013 |
11 | 477574978078 |
12 | 197979200991 |
13 | 995472167cb |
14 | 48c4c4d7417 |
15 | 24d0c3776ad |
hex | 1381de1ed7d |
1340531142013 has 8 divisors (see below), whose sum is σ = 1532083408128. Its totient is φ = 1148990830224.
The previous prime is 1340531142011. The next prime is 1340531142047. The reversal of 1340531142013 is 3102411350431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1340531142013 - 21 = 1340531142011 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340531142011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2746981 + ... + 3197962.
It is an arithmetic number, because the mean of its divisors is an integer number (191510426016).
Almost surely, 21340531142013 is an apocalyptic number.
It is an amenable number.
1340531142013 is a deficient number, since it is larger than the sum of its proper divisors (191552266115).
1340531142013 is an equidigital number, since it uses as much as digits as its factorization.
1340531142013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5977163.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1340531142013 its reverse (3102411350431), we get a palindrome (4442942492444).
The spelling of 1340531142013 in words is "one trillion, three hundred forty billion, five hundred thirty-one million, one hundred forty-two thousand, thirteen".
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