Base | Representation |
---|---|
bin | 1100001100010011000101… |
… | …1011001111000110000011 |
3 | 1202110112201220210212102002 |
4 | 3003010301123033012003 |
5 | 3224113301032412430 |
6 | 44302211012214215 |
7 | 2552336600142035 |
oct | 303046133170603 |
9 | 52415656725362 |
10 | 13405422154115 |
11 | 42a92313667a2 |
12 | 160608890a36b |
13 | 763183752674 |
14 | 344b7c379c55 |
15 | 183a8c0c4845 |
hex | c31316cf183 |
13405422154115 has 16 divisors (see below), whose sum is σ = 16360196486400. Its totient is φ = 10541900839392.
The previous prime is 13405422154081. The next prime is 13405422154127. The reversal of 13405422154115 is 51145122450431.
It is a cyclic number.
It is not a de Polignac number, because 13405422154115 - 28 = 13405422153859 is a prime.
It is a super-3 number, since 3×134054221541153 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3245714 + ... + 6111096.
It is an arithmetic number, because the mean of its divisors is an integer number (1022512280400).
Almost surely, 213405422154115 is an apocalyptic number.
13405422154115 is a deficient number, since it is larger than the sum of its proper divisors (2954774332285).
13405422154115 is a wasteful number, since it uses less digits than its factorization.
13405422154115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2881306.
The product of its (nonzero) digits is 96000, while the sum is 38.
The spelling of 13405422154115 in words is "thirteen trillion, four hundred five billion, four hundred twenty-two million, one hundred fifty-four thousand, one hundred fifteen".
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