13405424212451 has 4 divisors (see below), whose sum is σ = 13501866113400. Its totient is φ = 13308982311504.

The previous prime is 13405424212373. The next prime is 13405424212469. The reversal of 13405424212451 is 15421242450431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13405424212451 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13405424512451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48220950266 + ... + 48220950543.

It is an arithmetic number, because the mean of its divisors is an integer number (3375466528350).

Almost surely, 2^{13405424212451} is an apocalyptic number.

13405424212451 is a deficient number, since it is larger than the sum of its proper divisors (96441900949).

13405424212451 is an equidigital number, since it uses as much as digits as its factorization.

13405424212451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96441900948.

The product of its (nonzero) digits is 153600, while the sum is 38.

Adding to 13405424212451 its reverse (15421242450431), we get a palindrome (28826666662882).

The spelling of 13405424212451 in words is "thirteen trillion, four hundred five billion, four hundred twenty-four million, two hundred twelve thousand, four hundred fifty-one".