13405441043153 has 4 divisors (see below), whose sum is σ = 14110990571760. Its totient is φ = 12699891514548.

The previous prime is 13405441043149. The next prime is 13405441043207. The reversal of 13405441043153 is 35134014450431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13405441043153 - 2² = 13405441043149 is a prime.

It is a super-2 number, since 2×13405441043153² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13405441043053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352774764275 + ... + 352774764312.

It is an arithmetic number, because the mean of its divisors is an integer number (3527747642940).

Almost surely, 2^{13405441043153} is an apocalyptic number.

It is an amenable number.

13405441043153 is a deficient number, since it is larger than the sum of its proper divisors (705549528607).

13405441043153 is an equidigital number, since it uses as much as digits as its factorization.

13405441043153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 705549528606.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 13405441043153 its reverse (35134014450431), we get a palindrome (48539455493584).

The spelling of 13405441043153 in words is "thirteen trillion, four hundred five billion, four hundred forty-one million, forty-three thousand, one hundred fifty-three".