Base | Representation |
---|---|
bin | 1100001100010011011000… |
… | …1001101101010101001111 |
3 | 1202110112221110000021200101 |
4 | 3003010312021231111033 |
5 | 3224113431332223310 |
6 | 44302222523511531 |
7 | 2552341552124110 |
oct | 303046611552517 |
9 | 52415843007611 |
10 | 13405501445455 |
11 | 42a92720a3529 |
12 | 16060ab3885a7 |
13 | 763196cc5312 |
14 | 344b88ada207 |
15 | 183a9403843a |
hex | c313626d54f |
13405501445455 has 16 divisors (see below), whose sum is σ = 18386789944320. Its totient is φ = 9191292724512.
The previous prime is 13405501445389. The next prime is 13405501445507. The reversal of 13405501445455 is 55454410550431.
13405501445455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13405501445455 - 229 = 13404964574543 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21587895 + ... + 22200184.
It is an arithmetic number, because the mean of its divisors is an integer number (1149174371520).
Almost surely, 213405501445455 is an apocalyptic number.
13405501445455 is a deficient number, since it is larger than the sum of its proper divisors (4981288498865).
13405501445455 is an equidigital number, since it uses as much as digits as its factorization.
13405501445455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43796838.
The product of its (nonzero) digits is 2400000, while the sum is 46.
Adding to 13405501445455 its reverse (55454410550431), we get a palindrome (68859911995886).
The spelling of 13405501445455 in words is "thirteen trillion, four hundred five billion, five hundred one million, four hundred forty-five thousand, four hundred fifty-five".
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