13405504213445 has 4 divisors (see below), whose sum is σ = 16086605056140. Its totient is φ = 10724403370752.

The previous prime is 13405504213433. The next prime is 13405504213457. The reversal of 13405504213445 is 54431240550431.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13405504213433) and next prime (13405504213457).

It can be written as a sum of positive squares in 2 ways, for example, as 6320628415396 + 7084875798049 = 2514086^2 + 2661743^2 .

It is a cyclic number.

It is not a de Polignac number, because 13405504213445 - 2¹⁴ = 13405504197061 is a prime.

It is a super-3 number, since 3×13405504213445³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340550421340 + ... + 1340550421349.

It is an arithmetic number, because the mean of its divisors is an integer number (4021651264035).

Almost surely, 2^{13405504213445} is an apocalyptic number.

It is an amenable number.

13405504213445 is a deficient number, since it is larger than the sum of its proper divisors (2681100842695).

13405504213445 is an equidigital number, since it uses as much as digits as its factorization.

13405504213445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2681100842694.

The product of its (nonzero) digits is 576000, while the sum is 41.

Adding to 13405504213445 its reverse (54431240550431), we get a palindrome (67836744763876).

The spelling of 13405504213445 in words is "thirteen trillion, four hundred five billion, five hundred four million, two hundred thirteen thousand, four hundred forty-five".