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1340555154441 = 3446851718147
BaseRepresentation
bin10011100000011111010…
…100000101010000001001
311202011012121000202110020
4103200133110011100021
5133430424104420231
62503501553211053
7165565130542266
oct23403724052011
94664177022406
101340555154441
11477587488a58
12197985260a89
139954c1a3349
1448c5178826d
1524d0e51c396
hex1381f505409

1340555154441 has 4 divisors (see below), whose sum is σ = 1787406872592. Its totient is φ = 893703436292.

The previous prime is 1340555154431. The next prime is 1340555154509. The reversal of 1340555154441 is 1444515550431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340555154441 - 27 = 1340555154313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340555154393 and 1340555154402.

It is not an unprimeable number, because it can be changed into a prime (1340555154431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223425859071 + ... + 223425859076.

It is an arithmetic number, because the mean of its divisors is an integer number (446851718148).

Almost surely, 21340555154441 is an apocalyptic number.

It is an amenable number.

1340555154441 is a deficient number, since it is larger than the sum of its proper divisors (446851718151).

1340555154441 is an equidigital number, since it uses as much as digits as its factorization.

1340555154441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 446851718150.

The product of its (nonzero) digits is 480000, while the sum is 42.

The spelling of 1340555154441 in words is "one trillion, three hundred forty billion, five hundred fifty-five million, one hundred fifty-four thousand, four hundred forty-one".

Divisors: 1 3 446851718147 1340555154441