Base | Representation |
---|---|
bin | 11000111110001000… |
… | …00000001000110011 |
3 | 1021121021211122002221 |
4 | 30133010000020303 |
5 | 204423421412343 |
6 | 10054134021511 |
7 | 653133333331 |
oct | 143704001063 |
9 | 37537748087 |
10 | 13406044723 |
11 | 575a3a9905 |
12 | 27217a7897 |
13 | 135854b756 |
14 | 912664b51 |
15 | 536e0b5ed |
hex | 31f100233 |
13406044723 has 4 divisors (see below), whose sum is σ = 13633265880. Its totient is φ = 13178823568.
The previous prime is 13406044693. The next prime is 13406044747. The reversal of 13406044723 is 32744060431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13406044723 is a prime.
It is a super-2 number, since 2×134060447232 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13406044793) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113610490 + ... + 113610607.
It is an arithmetic number, because the mean of its divisors is an integer number (3408316470).
Almost surely, 213406044723 is an apocalyptic number.
13406044723 is a deficient number, since it is larger than the sum of its proper divisors (227221157).
13406044723 is an equidigital number, since it uses as much as digits as its factorization.
13406044723 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 227221156.
The product of its (nonzero) digits is 48384, while the sum is 34.
The spelling of 13406044723 in words is "thirteen billion, four hundred six million, forty-four thousand, seven hundred twenty-three".
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