134060801139631 has 4 divisors (see below), whose sum is σ = 134295583629064. Its totient is φ = 133826018650200.

The previous prime is 134060801139541. The next prime is 134060801139641. The reversal of 134060801139631 is 136931108060431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134060801139631 is a prime.

It is a super-2 number, since 2×134060801139631² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134060801139641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117391243860 + ... + 117391245001.

It is an arithmetic number, because the mean of its divisors is an integer number (33573895907266).

Almost surely, 2^{134060801139631} is an apocalyptic number.

134060801139631 is a deficient number, since it is larger than the sum of its proper divisors (234782489433).

134060801139631 is an equidigital number, since it uses as much as digits as its factorization.

134060801139631 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 234782489432.

The product of its (nonzero) digits is 279936, while the sum is 46.

The spelling of 134060801139631 in words is "one hundred thirty-four trillion, sixty billion, eight hundred one million, one hundred thirty-nine thousand, six hundred thirty-one".