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13406267433 = 3131073379533
BaseRepresentation
bin11000111110001001…
…10110100000101001
31021121022020221121110
430133010312200221
5204424001024213
610054142500533
7653135251536
oct143704664051
937538227543
1013406267433
11575a541169
122721894749
1313585c8c30
149126c1d8d
15536e525c3
hex31f136829

13406267433 has 32 divisors (see below), whose sum is σ = 19489631616. Its totient is φ = 8147801088.

The previous prime is 13406267429. The next prime is 13406267449. The reversal of 13406267433 is 33476260431.

It is not a de Polignac number, because 13406267433 - 22 = 13406267429 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a junction number, because it is equal to n+sod(n) for n = 13406267391 and 13406267400.

It is not an unprimeable number, because it can be changed into a prime (13406277433) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1401535 + ... + 1411067.

It is an arithmetic number, because the mean of its divisors is an integer number (609050988).

Almost surely, 213406267433 is an apocalyptic number.

13406267433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13406267433 is a deficient number, since it is larger than the sum of its proper divisors (6083364183).

13406267433 is a wasteful number, since it uses less digits than its factorization.

13406267433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9993.

The product of its (nonzero) digits is 217728, while the sum is 39.

The spelling of 13406267433 in words is "thirteen billion, four hundred six million, two hundred sixty-seven thousand, four hundred thirty-three".

Divisors: 1 3 13 39 107 321 337 1011 1391 4173 4381 9533 13143 28599 36059 108177 123929 371787 468767 1020031 1406301 3060093 3212621 9637863 13260403 39781209 41764073 125292219 343750447 1031251341 4468755811 13406267433