Base | Representation |
---|---|
bin | 111110011011011111… |
… | …0011100001010100011 |
3 | 110211001022102220200021 |
4 | 1330312332130022203 |
5 | 4144031434333011 |
6 | 141331134334311 |
7 | 12454200644515 |
oct | 1746676341243 |
9 | 424038386607 |
10 | 134066324131 |
11 | 51947a43693 |
12 | 21b9665a397 |
13 | c84747889c |
14 | 66bb565bb5 |
15 | 3749d3a471 |
hex | 1f36f9c2a3 |
134066324131 has 4 divisors (see below), whose sum is σ = 135030830200. Its totient is φ = 133101818064.
The previous prime is 134066324087. The next prime is 134066324149. The reversal of 134066324131 is 131423660431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134066324131 - 27 = 134066324003 is a prime.
It is a super-2 number, since 2×1340663241312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134066324731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 482252826 + ... + 482253103.
It is an arithmetic number, because the mean of its divisors is an integer number (33757707550).
Almost surely, 2134066324131 is an apocalyptic number.
134066324131 is a deficient number, since it is larger than the sum of its proper divisors (964506069).
134066324131 is an equidigital number, since it uses as much as digits as its factorization.
134066324131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 964506068.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 134066324131 its reverse (131423660431), we get a palindrome (265489984562).
The spelling of 134066324131 in words is "one hundred thirty-four billion, sixty-six million, three hundred twenty-four thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •