134068133 has 4 divisors (see below), whose sum is σ = 134094240. Its totient is φ = 134042028.

The previous prime is 134068117. The next prime is 134068159. The reversal of 134068133 is 331860431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 134068133 - 2⁴ = 134068117 is a prime.

It is a super-2 number, since 2×134068133² = 35948528572211378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134068096 and 134068105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134068183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2513 + ... + 16566.

It is an arithmetic number, because the mean of its divisors is an integer number (33523560).

Almost surely, 2^134068133 is an apocalyptic number.

It is an amenable number.

134068133 is a deficient number, since it is larger than the sum of its proper divisors (26107).

134068133 is an equidigital number, since it uses as much as digits as its factorization.

134068133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26106.

The product of its (nonzero) digits is 5184, while the sum is 29.

The square root of 134068133 is about 11578.7794261744. The cubic root of 134068133 is about 511.8097094060.

The spelling of 134068133 in words is "one hundred thirty-four million, sixty-eight thousand, one hundred thirty-three".