Base | Representation |
---|---|
bin | 1100001100011011000111… |
… | …1101001010010101100011 |
3 | 1202110202022012102011121222 |
4 | 3003012301331022111203 |
5 | 3224132210100444141 |
6 | 44303205003005255 |
7 | 2552444203063436 |
oct | 303066175122543 |
9 | 52422265364558 |
10 | 13407578531171 |
11 | 42aa1386007a0 |
12 | 160658ab0982b |
13 | 76343841c416 |
14 | 344d048dd81d |
15 | 183b6657614b |
hex | c31b1f4a563 |
13407578531171 has 16 divisors (see below), whose sum is σ = 14807040288768. Its totient is φ = 12038301952800.
The previous prime is 13407578531167. The next prime is 13407578531201. The reversal of 13407578531171 is 17113587570431.
13407578531171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13407578531171 - 22 = 13407578531167 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13407578534171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 930665 + ... + 5261301.
It is an arithmetic number, because the mean of its divisors is an integer number (925440018048).
Almost surely, 213407578531171 is an apocalyptic number.
13407578531171 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13407578531171 is a deficient number, since it is larger than the sum of its proper divisors (1399461757597).
13407578531171 is a wasteful number, since it uses less digits than its factorization.
13407578531171 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4334122.
The product of its (nonzero) digits is 2469600, while the sum is 53.
The spelling of 13407578531171 in words is "thirteen trillion, four hundred seven billion, five hundred seventy-eight million, five hundred thirty-one thousand, one hundred seventy-one".
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