Base | Representation |
---|---|
bin | 11110011111011010101001… |
… | …100101101011010110011111 |
3 | 122120210212100110110101220200 |
4 | 132133122221211223112133 |
5 | 120034044420410021421 |
6 | 1153112500040114543 |
7 | 40150266536643402 |
oct | 3637325145532637 |
9 | 576725313411820 |
10 | 134100314142111 |
11 | 39801695388579 |
12 | 13059657a65a53 |
13 | 59a97b3ca0155 |
14 | 25186c0173d39 |
15 | 10783cc142726 |
hex | 79f6a996b59f |
134100314142111 has 6 divisors (see below), whose sum is σ = 193700453760840. Its totient is φ = 89400209428068.
The previous prime is 134100314142107. The next prime is 134100314142121. The reversal of 134100314142111 is 111241413001431.
134100314142111 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 0 + 0 + 31 + 414 + 211 + 1 = 666.
It is not a de Polignac number, because 134100314142111 - 22 = 134100314142107 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134100314142121) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7450017452331 + ... + 7450017452348.
It is an arithmetic number, because the mean of its divisors is an integer number (32283408960140).
Almost surely, 2134100314142111 is an apocalyptic number.
134100314142111 is a deficient number, since it is larger than the sum of its proper divisors (59600139618729).
134100314142111 is a wasteful number, since it uses less digits than its factorization.
134100314142111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14900034904685 (or 14900034904682 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 27.
Adding to 134100314142111 its reverse (111241413001431), we get a palindrome (245341727143542).
The spelling of 134100314142111 in words is "one hundred thirty-four trillion, one hundred billion, three hundred fourteen million, one hundred forty-two thousand, one hundred eleven".
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