Base | Representation |
---|---|
bin | 11110011111011101011100… |
… | …011101100000000100010101 |
3 | 122120211011002121022220012220 |
4 | 132133131130131200010111 |
5 | 120034122042132323110 |
6 | 1153114113521332553 |
7 | 40150434106562301 |
oct | 3637353435400425 |
9 | 576734077286186 |
10 | 134103315120405 |
11 | 39802995356a24 |
12 | 1305a154a97159 |
13 | 59a9b71937a57 |
14 | 25188c6952d01 |
15 | 107850582b370 |
hex | 79f75c760115 |
134103315120405 has 16 divisors (see below), whose sum is σ = 214566424459200. Its totient is φ = 71521394642048.
The previous prime is 134103315120373. The next prime is 134103315120419. The reversal of 134103315120405 is 504021513301431.
It is a cyclic number.
It is not a de Polignac number, because 134103315120405 - 25 = 134103315120373 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20357880 + ... + 26127569.
It is an arithmetic number, because the mean of its divisors is an integer number (13410401528700).
Almost surely, 2134103315120405 is an apocalyptic number.
134103315120405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
134103315120405 is a deficient number, since it is larger than the sum of its proper divisors (80463109338795).
134103315120405 is a wasteful number, since it uses less digits than its factorization.
134103315120405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46677780.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 134103315120405 its reverse (504021513301431), we get a palindrome (638124828421836).
The spelling of 134103315120405 in words is "one hundred thirty-four trillion, one hundred three billion, three hundred fifteen million, one hundred twenty thousand, four hundred five".
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