Base | Representation |
---|---|
bin | 1100001100100110000011… |
… | …0101000111010010110010 |
3 | 1202111000212200001220011211 |
4 | 3003021200311013102302 |
5 | 3224204212140344404 |
6 | 44304412050430334 |
7 | 2552606666620150 |
oct | 303114065072262 |
9 | 52430780056154 |
10 | 13410512434354 |
11 | 4300403726672 |
12 | 16070695923aa |
13 | 7637b52008c9 |
14 | 34510241c3d0 |
15 | 183c88e10b04 |
hex | c3260d474b2 |
13410512434354 has 8 divisors (see below), whose sum is σ = 22989449887488. Its totient is φ = 5747362471860.
The previous prime is 13410512434351. The next prime is 13410512434441. The reversal of 13410512434354 is 45343421501431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not an unprimeable number, because it can be changed into a prime (13410512434351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 478946872642 + ... + 478946872669.
It is an arithmetic number, because the mean of its divisors is an integer number (2873681235936).
Almost surely, 213410512434354 is an apocalyptic number.
13410512434354 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13410512434354 is a deficient number, since it is larger than the sum of its proper divisors (9578937453134).
13410512434354 is an equidigital number, since it uses as much as digits as its factorization.
13410512434354 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 957893745320.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 13410512434354 its reverse (45343421501431), we get a palindrome (58753933935785).
The spelling of 13410512434354 in words is "thirteen trillion, four hundred ten billion, five hundred twelve million, four hundred thirty-four thousand, three hundred fifty-four".
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