13410531403341 has 4 divisors (see below), whose sum is σ = 17880708537792. Its totient is φ = 8940354268892.

The previous prime is 13410531403337. The next prime is 13410531403343. The reversal of 13410531403341 is 14330413501431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13410531403341 - 2² = 13410531403337 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13410531403343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2235088567221 + ... + 2235088567226.

It is an arithmetic number, because the mean of its divisors is an integer number (4470177134448).

Almost surely, 2^{13410531403341} is an apocalyptic number.

It is an amenable number.

13410531403341 is a deficient number, since it is larger than the sum of its proper divisors (4470177134451).

13410531403341 is an equidigital number, since it uses as much as digits as its factorization.

13410531403341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4470177134450.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 13410531403341 its reverse (14330413501431), we get a palindrome (27740944904772).

The spelling of 13410531403341 in words is "thirteen trillion, four hundred ten billion, five hundred thirty-one million, four hundred three thousand, three hundred forty-one".