13410533450403 has 10 divisors (see below), whose sum is σ = 20033019105044. Its totient is φ = 8940355633548.

The previous prime is 13410533450401. The next prime is 13410533450417. The reversal of 13410533450403 is 30405433501431.

13410533450403 is a `hidden beast` number, since 1 + 3 + 41 + 0 + 533 + 45 + 0 + 40 + 3 = 666.

It is not a de Polignac number, because 13410533450403 - 2¹ = 13410533450401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13410533450401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 82781070601 + ... + 82781070762.

Almost surely, 2^{13410533450403} is an apocalyptic number.

13410533450403 is a deficient number, since it is larger than the sum of its proper divisors (6622485654641).

13410533450403 is an equidigital number, since it uses as much as digits as its factorization.

13410533450403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165562141375 (or 165562141366 counting only the distinct ones).

The product of its (nonzero) digits is 129600, while the sum is 36.

Adding to 13410533450403 its reverse (30405433501431), we get a palindrome (43815966951834).

The spelling of 13410533450403 in words is "thirteen trillion, four hundred ten billion, five hundred thirty-three million, four hundred fifty thousand, four hundred three".