1341100232433 has 40 divisors (see below), whose sum is σ = 2157918047208. Its totient is φ = 825123926016.

The previous prime is 1341100232431. The next prime is 1341100232477. The reversal of 1341100232433 is 3342320011431.

It is a happy number.

1341100232433 is a `hidden beast` number, since 1 + 3 + 411 + 0 + 0 + 2 + 3 + 243 + 3 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 54490965489 + 1286609266944 = 233433^2 + 1134288^2 .

It is not a de Polignac number, because 1341100232433 - 2¹ = 1341100232431 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1341100232397 and 1341100232406.

It is not an unprimeable number, because it can be changed into a prime (1341100232431) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 5130091 + ... + 5385167.

Almost surely, 2^{1341100232433} is an apocalyptic number.

1341100232433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1341100232433 is a deficient number, since it is larger than the sum of its proper divisors (816817814775).

1341100232433 is a wasteful number, since it uses less digits than its factorization.

1341100232433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260095 (or 260086 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 1341100232433 its reverse (3342320011431), we get a palindrome (4683420243864).

The spelling of 1341100232433 in words is "one trillion, three hundred forty-one billion, one hundred million, two hundred thirty-two thousand, four hundred thirty-three".