13411011032213 has 4 divisors (see below), whose sum is σ = 13411019423040. Its totient is φ = 13411002641388.

The previous prime is 13411011032203. The next prime is 13411011032239. The reversal of 13411011032213 is 31223011011431.

13411011032213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13411011032213 is a prime.

It is a super-2 number, since 2×13411011032213² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13411011032203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 972893 + ... + 5269586.

It is an arithmetic number, because the mean of its divisors is an integer number (3352754855760).

Almost surely, 2^{13411011032213} is an apocalyptic number.

It is an amenable number.

13411011032213 is a deficient number, since it is larger than the sum of its proper divisors (8390827).

13411011032213 is an equidigital number, since it uses as much as digits as its factorization.

13411011032213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8390826.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13411011032213 its reverse (31223011011431), we get a palindrome (44634022043644).

The spelling of 13411011032213 in words is "thirteen trillion, four hundred eleven billion, eleven million, thirty-two thousand, two hundred thirteen".