Base | Representation |
---|---|
bin | 1100001100101000000010… |
… | …0010110111010111100101 |
3 | 1202111002020202021201110010 |
4 | 3003022000202313113211 |
5 | 3224211304344141240 |
6 | 44304540535120433 |
7 | 2552626120364364 |
oct | 303120042672745 |
9 | 52432222251403 |
10 | 13411044521445 |
11 | 430065700956a |
12 | 1607197813119 |
13 | 76386b50b93c |
14 | 345152d677db |
15 | 183cba9b6280 |
hex | c32808b75e5 |
13411044521445 has 16 divisors (see below), whose sum is σ = 21481329107520. Its totient is φ = 7144671120384.
The previous prime is 13411044521389. The next prime is 13411044521521. The reversal of 13411044521445 is 54412544011431.
It is not a de Polignac number, because 13411044521445 - 27 = 13411044521317 is a prime.
It is a super-2 number, since 2×134110445214452 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 492858300 + ... + 492885509.
It is an arithmetic number, because the mean of its divisors is an integer number (1342583069220).
Almost surely, 213411044521445 is an apocalyptic number.
13411044521445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13411044521445 is a deficient number, since it is larger than the sum of its proper divisors (8070284586075).
13411044521445 is an equidigital number, since it uses as much as digits as its factorization.
13411044521445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 985744724.
The product of its (nonzero) digits is 153600, while the sum is 39.
Adding to 13411044521445 its reverse (54412544011431), we get a palindrome (67823588532876).
The spelling of 13411044521445 in words is "thirteen trillion, four hundred eleven billion, forty-four million, five hundred twenty-one thousand, four hundred forty-five".
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