1341110432401 has 4 divisors (see below), whose sum is σ = 1372299047152. Its totient is φ = 1309921817652.

The previous prime is 1341110432383. The next prime is 1341110432437. The reversal of 1341110432401 is 1042340111431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1341110432401 - 2¹⁵ = 1341110399633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341110438401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15594307311 + ... + 15594307396.

It is an arithmetic number, because the mean of its divisors is an integer number (343074761788).

Almost surely, 2^{1341110432401} is an apocalyptic number.

It is an amenable number.

1341110432401 is a deficient number, since it is larger than the sum of its proper divisors (31188614751).

1341110432401 is an equidigital number, since it uses as much as digits as its factorization.

1341110432401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31188614750.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1341110432401 its reverse (1042340111431), we get a palindrome (2383450543832).

The spelling of 1341110432401 in words is "one trillion, three hundred forty-one billion, one hundred ten million, four hundred thirty-two thousand, four hundred one".