1341112433 has 4 divisors (see below), whose sum is σ = 1341192048. Its totient is φ = 1341032820.

The previous prime is 1341112403. The next prime is 1341112447. The reversal of 1341112433 is 3342111431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3342111431 = 131 ⋅25512301.

It is a cyclic number.

It is not a de Polignac number, because 1341112433 - 2⁸ = 1341112177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1341112399 and 1341112408.

It is not an unprimeable number, because it can be changed into a prime (1341112403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3503 + ... + 51908.

It is an arithmetic number, because the mean of its divisors is an integer number (335298012).

Almost surely, 2^1341112433 is an apocalyptic number.

It is an amenable number.

1341112433 is a deficient number, since it is larger than the sum of its proper divisors (79615).

1341112433 is an equidigital number, since it uses as much as digits as its factorization.

1341112433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79614.

The product of its digits is 864, while the sum is 23.

The square root of 1341112433 is about 36621.2019600668. The cubic root of 1341112433 is about 1102.7787687081.

Adding to 1341112433 its reverse (3342111431), we get a palindrome (4683223864).

The spelling of 1341112433 in words is "one billion, three hundred forty-one million, one hundred twelve thousand, four hundred thirty-three".