13411242131143 has 4 divisors (see below), whose sum is σ = 13411789352280. Its totient is φ = 13410694910008.

The previous prime is 13411242131069. The next prime is 13411242131153. The reversal of 13411242131143 is 34113124211431.

13411242131143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13411242131143 is a prime.

It is a super-2 number, since 2×13411242131143² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13411242131153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273573805 + ... + 273622822.

It is an arithmetic number, because the mean of its divisors is an integer number (3352947338070).

Almost surely, 2^{13411242131143} is an apocalyptic number.

13411242131143 is a deficient number, since it is larger than the sum of its proper divisors (547221137).

13411242131143 is an equidigital number, since it uses as much as digits as its factorization.

13411242131143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 547221136.

The product of its digits is 6912, while the sum is 31.

Adding to 13411242131143 its reverse (34113124211431), we get a palindrome (47524366342574).

The spelling of 13411242131143 in words is "thirteen trillion, four hundred eleven billion, two hundred forty-two million, one hundred thirty-one thousand, one hundred forty-three".