13411310420000 has 240 divisors, whose sum is σ = 34925375802240. Its totient is φ = 5059076736000.

The previous prime is 13411310419973. The next prime is 13411310420051. The reversal of 13411310420000 is 2401311431.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 24671129 + ... + 25208871.

It is an arithmetic number, because the mean of its divisors is an integer number (145522399176).

Almost surely, 2^{13411310420000} is an apocalyptic number.

13411310420000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13411310420000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17462687901120).

13411310420000 is an abundant number, since it is smaller than the sum of its proper divisors (21514065382240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13411310420000 is an equidigital number, since it uses as much as digits as its factorization.

13411310420000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 537845 (or 537822 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13411310420000 its reverse (2401311431), we get a palindrome (13413711731431).

The spelling of 13411310420000 in words is "thirteen trillion, four hundred eleven billion, three hundred ten million, four hundred twenty thousand".