13411324661335 has 4 divisors (see below), whose sum is σ = 16093589593608. Its totient is φ = 10729059729064.

The previous prime is 13411324661321. The next prime is 13411324661393. The reversal of 13411324661335 is 53316642311431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13411324661335 - 2²⁹ = 13410787790423 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13411324661291 and 13411324661300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1341132466129 + ... + 1341132466138.

It is an arithmetic number, because the mean of its divisors is an integer number (4023397398402).

Almost surely, 2^{13411324661335} is an apocalyptic number.

13411324661335 is a deficient number, since it is larger than the sum of its proper divisors (2682264932273).

13411324661335 is an equidigital number, since it uses as much as digits as its factorization.

13411324661335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2682264932272.

The product of its digits is 466560, while the sum is 43.

Adding to 13411324661335 its reverse (53316642311431), we get a palindrome (66727966972766).

The spelling of 13411324661335 in words is "thirteen trillion, four hundred eleven billion, three hundred twenty-four million, six hundred sixty-one thousand, three hundred thirty-five".