13411503132133 has 4 divisors (see below), whose sum is σ = 14200415081100. Its totient is φ = 12622591183168.

The previous prime is 13411503132101. The next prime is 13411503132179. The reversal of 13411503132133 is 33123130511431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11503065874689 + 1908437257444 = 3391617^2 + 1381462^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411503132133 - 2⁵ = 13411503132101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13411503132095 and 13411503132104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13411503138133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 394455974458 + ... + 394455974491.

It is an arithmetic number, because the mean of its divisors is an integer number (3550103770275).

Almost surely, 2^{13411503132133} is an apocalyptic number.

It is an amenable number.

13411503132133 is a deficient number, since it is larger than the sum of its proper divisors (788911948967).

13411503132133 is an equidigital number, since it uses as much as digits as its factorization.

13411503132133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 788911948966.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 13411503132133 its reverse (33123130511431), we get a palindrome (46534633643564).

The spelling of 13411503132133 in words is "thirteen trillion, four hundred eleven billion, five hundred three million, one hundred thirty-two thousand, one hundred thirty-three".