Base | Representation |
---|---|
bin | 10011100001000011000… |
… | …001011100111100110111 |
3 | 11202012202100022222211001 |
4 | 103201003001130330313 |
5 | 133433140442004201 |
6 | 2504041234024131 |
7 | 165616024015213 |
oct | 23410301347467 |
9 | 4665670288731 |
10 | 1341154250551 |
11 | 477864679805 |
12 | 197b11a18047 |
13 | 9961634369b |
14 | 48cab177943 |
15 | 24d46e0c301 |
hex | 1384305cf37 |
1341154250551 has 8 divisors (see below), whose sum is σ = 1420221375360. Its totient is φ = 1262106647808.
The previous prime is 1341154250543. The next prime is 1341154250591. The reversal of 1341154250551 is 1550524511431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1341154250551 - 23 = 1341154250543 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1341154250551.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1341154250591) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4738951 + ... + 5013976.
It is an arithmetic number, because the mean of its divisors is an integer number (177527671920).
Almost surely, 21341154250551 is an apocalyptic number.
1341154250551 is a deficient number, since it is larger than the sum of its proper divisors (79067124809).
1341154250551 is an equidigital number, since it uses as much as digits as its factorization.
1341154250551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9761033.
The product of its (nonzero) digits is 60000, while the sum is 37.
Adding to 1341154250551 its reverse (1550524511431), we get a palindrome (2891678761982).
The spelling of 1341154250551 in words is "one trillion, three hundred forty-one billion, one hundred fifty-four million, two hundred fifty thousand, five hundred fifty-one".
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