Base | Representation |
---|---|
bin | 11000111110110101… |
… | …10000100010001001 |
3 | 1021121201001201002121 |
4 | 30133122300202021 |
5 | 204431433310441 |
6 | 10054505531241 |
7 | 653235130216 |
oct | 143732604211 |
9 | 37551051077 |
10 | 13412010121 |
11 | 5762803794 |
12 | 27237a3b21 |
13 | 1359859a83 |
14 | 913378b0d |
15 | 5376d8dd1 |
hex | 31f6b0889 |
13412010121 has 4 divisors (see below), whose sum is σ = 13600911744. Its totient is φ = 13223108500.
The previous prime is 13412010113. The next prime is 13412010137. The reversal of 13412010121 is 12101021431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13412010121 - 23 = 13412010113 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13412010095 and 13412010104.
It is not an unprimeable number, because it can be changed into a prime (13412010151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94450705 + ... + 94450846.
It is an arithmetic number, because the mean of its divisors is an integer number (3400227936).
Almost surely, 213412010121 is an apocalyptic number.
It is an amenable number.
13412010121 is a deficient number, since it is larger than the sum of its proper divisors (188901623).
13412010121 is an equidigital number, since it uses as much as digits as its factorization.
13412010121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 188901622.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 13412010121 its reverse (12101021431), we get a palindrome (25513031552).
The spelling of 13412010121 in words is "thirteen billion, four hundred twelve million, ten thousand, one hundred twenty-one".
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