Base | Representation |
---|---|
bin | 11000111110110101… |
… | …10000100010100111 |
3 | 1021121201001201010201 |
4 | 30133122300202213 |
5 | 204431433311101 |
6 | 10054505531331 |
7 | 653235130261 |
oct | 143732604247 |
9 | 37551051121 |
10 | 13412010151 |
11 | 5762803811 |
12 | 27237a3b47 |
13 | 1359859aa7 |
14 | 913378b31 |
15 | 5376d8e01 |
hex | 31f6b08a7 |
13412010151 has 2 divisors, whose sum is σ = 13412010152. Its totient is φ = 13412010150.
The previous prime is 13412010137. The next prime is 13412010163. The reversal of 13412010151 is 15101021431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13412010151 - 27 = 13412010023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13412010181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706005075 + 6706005076.
It is an arithmetic number, because the mean of its divisors is an integer number (6706005076).
Almost surely, 213412010151 is an apocalyptic number.
13412010151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13412010151 is an equidigital number, since it uses as much as digits as its factorization.
13412010151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 13412010151 its reverse (15101021431), we get a palindrome (28513031582).
The spelling of 13412010151 in words is "thirteen billion, four hundred twelve million, ten thousand, one hundred fifty-one".
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