Base | Representation |
---|---|
bin | 1100001100101011101001… |
… | …0011001110111111100011 |
3 | 1202111011202021121001110221 |
4 | 3003022322103032333203 |
5 | 3224220300424034220 |
6 | 44305221031503511 |
7 | 2552662124524012 |
oct | 303127223167743 |
9 | 52434667531427 |
10 | 13412013502435 |
11 | 4301003a762a9 |
12 | 1607408227b97 |
13 | 7639941a8082 |
14 | 34520591ca79 |
15 | 183d25abb9aa |
hex | c32ba4cefe3 |
13412013502435 has 8 divisors (see below), whose sum is σ = 16794173429280. Its totient is φ = 10263105984384.
The previous prime is 13412013502417. The next prime is 13412013502463. The reversal of 13412013502435 is 53420531021431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13412013502435 - 25 = 13412013502403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13412013502435.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58313102070 + ... + 58313102299.
It is an arithmetic number, because the mean of its divisors is an integer number (2099271678660).
Almost surely, 213412013502435 is an apocalyptic number.
13412013502435 is a deficient number, since it is larger than the sum of its proper divisors (3382159926845).
13412013502435 is a wasteful number, since it uses less digits than its factorization.
13412013502435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 116626204397.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 13412013502435 its reverse (53420531021431), we get a palindrome (66832544523866).
The spelling of 13412013502435 in words is "thirteen trillion, four hundred twelve billion, thirteen million, five hundred two thousand, four hundred thirty-five".
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