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13412013502435 = 523116626204369
BaseRepresentation
bin1100001100101011101001…
…0011001110111111100011
31202111011202021121001110221
43003022322103032333203
53224220300424034220
644305221031503511
72552662124524012
oct303127223167743
952434667531427
1013412013502435
114301003a762a9
121607408227b97
137639941a8082
1434520591ca79
15183d25abb9aa
hexc32ba4cefe3

13412013502435 has 8 divisors (see below), whose sum is σ = 16794173429280. Its totient is φ = 10263105984384.

The previous prime is 13412013502417. The next prime is 13412013502463. The reversal of 13412013502435 is 53420531021431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13412013502435 - 25 = 13412013502403 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13412013502435.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58313102070 + ... + 58313102299.

It is an arithmetic number, because the mean of its divisors is an integer number (2099271678660).

Almost surely, 213412013502435 is an apocalyptic number.

13412013502435 is a deficient number, since it is larger than the sum of its proper divisors (3382159926845).

13412013502435 is a wasteful number, since it uses less digits than its factorization.

13412013502435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 116626204397.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 13412013502435 its reverse (53420531021431), we get a palindrome (66832544523866).

The spelling of 13412013502435 in words is "thirteen trillion, four hundred twelve billion, thirteen million, five hundred two thousand, four hundred thirty-five".

Divisors: 1 5 23 115 116626204369 583131021845 2682402700487 13412013502435